Question

derive the formula of area of quadrilateral whose vertices are( x1,y1),(x2, y2), (x3, y3),(x4, y4)
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Answer 1

Answer:

Let vertices are A=(x₁,y₁),B=(x₂,y₂),C=(x₃,y₃),D=(x₄,y₄)

Mid point of diagonal AC=(x₁+x₃)/2,(y₁+y₃)/2

Mid point of diagonal BD=(x₂+x₄)/2,(y₂+y₄)/2

In parallelogram diagonal bisect each other at the same points

Therefore:-

(x₁+x₃)/2=(x₂+x₄)/2

x₁+x₃=x₂+x₄

Similarly:-

y₁+y₃=y₂+y₄

Step-by-step explanation:

hope this will help you it takes some minute to solve ❣️