Physics, asked by rushabhjainavv, 10 months ago

Derive the formula of elongation of tapered bar with rectangular cross section under it's own weight?

Answers

Answered by gauravarduino
0

Explanation:

Elongation of Prismatic bar under its self weight And comparison between ... Load acting on any cross-section of the member by method of section ... Introduction of Pure Bending and Bending equation.

Answered by netta00
0

Answer:

\Delta =\dfrac{WL}{2AE}

Explanation:

Lets take

Length of the bar = L

Cross sectional area = A

Young modulus = E

Total weight of the bar = W

Weight per unit volume

\rho=\dfrac{W}{AL}

The wight of the lower part

w=ρ A dx

The elongation of elemental part

d\Delta =\dfrac{\rho\ A\ x}{AE}dx\\\Delta =\int_{0}^{L}\dfrac{\rho\ A\ x}{AE}dx\\\Delta =\int_{0}^{L}\dfrac{\rho\ x}{E}dx\\\Delta =\left[\dfrac{\rho\ x^2}{2E}\right]_0^L\\\Delta =\dfrac{\rho\ L^2}{2E}\\\rho=\dfrac{W}{AL}\\\Delta =\dfrac{WL}{2AE}

Therefore the elongation due to self weight of the bar will be

\Delta =\dfrac{WL}{2AE}

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