Question

Derive the formula of first order reaction for
1) Rate constant K
2) Half life period t half​

Answer 1

Answer:

rate constant k is till the box

Answer 2

Answer:

For a first order reaction differential rate law can be written as:

−

dt

dA

= k[A] where k is the rate constant of first order reaction

Integrating the above equation we can write the first order rate law expression as:

[A]

t

=[A]

o

e

−kt

or kt=2.303 log

[A]

t

[A]

o

For, half life period, [A]

t

=[A]

o

/2

Therefore, t

1/2

=

k

2.303 log 2

or t

1/2

=

k

ln 2

Explanation:

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