Question

derive the formula of kinetic energy of particle and velocity using dimensional analysis​

Answer 1

Answer:

This is your well defined answer

Explanation:

# ke = 1/2 MV^2

# [KE] = [ 1/2 MV^2]

# [KE] = [ M ] * [ LT^-1]^2

# [KE] = [ML^2T^-2]

Thank$

Answer 2

Answer:

Energy is given in joules which is kg metre square par second square and since kinetic energy is also kind of energy it will have the same unit changing this unit in form of dimensions we get

$kg \frac{ {m}^{2} }{ {s}^{2} } = m {l}^{2} {t}^{ - 2} = (1)$

no the expression for kinetic energy is given as

$\frac{1}{2}m {v}^{2}$

changing this in form of dimensions of M is mass, V is velocity is given by distance per unit time

$= m {v}^{2} = m \frac{ {l}^{2} }{ {t}^{2} } = m {l}^{2} {t}^{ - 2} = (1)$

from equation 1 and 2 we can say

$k.e. = \frac{1}{2} m {v}^{2}$