Math, asked by Anonymous, 9 months ago

Derive the formula of sum of terms of HP​

Answers

Answered by 165
1

Answer:

A series of terms is known as a HP series when their reciprocals are in arithmetic progression. Example: 1/a, 1/(a+d), 1/(a+2d), and so on are in HP because a, a + d, a + 2d are in AP. The nth term of a HP series is Tn =1/ [a + (n -1) d].

Step-by-step explanation:

<body aquacolor=b>

\large\orange{}<font color=Red>

<marquee>☺️☺️☺️☺️☺️☺️☺️

<marquee>☺hi 165 here☺️

❤️❤️How are you all guys ❤️❤️

<marquee>☺️☺️☺️☺️☺️☺️☺️

<body bgcolor=green>

\large\orange{}<font color=Red>

Answered by sarivuselvi
0

Step-by-step explanation:

The nth term of the Harmonic Progression (H.P) = 1/ [a+(n-1)d]

Where

“a” is the first term of A.P

“d” is the common difference

“n” is the number of terms in A.P

The above formula can also be written as:

The nth term of H.P = 1/ (nth term of the corresponding A.P)

Geometric Progression

Arithmetic Progression for Class 10

Sum of N-terms

Sequence and Series

Harmonic Progression Sum

If 1/a, 1/a+d, 1/a+2d, …., 1/a+(n-1)d is given harmonic progression, the formula to find the sum of n terms in the harmonic progression is given by the formula:

Sum of n terms, Sn=1dln{2a+(2n−1)d2a−d}

Where,

“a” is the first term of A.P

“d” is the common difference of A.P

“ln” is the natural logarithm

Similar questions