Question

derive the formula Sin of a + b + c​

Answer 1

➡ sin [(a + b) + c ]

✒ sin (α + ß) = sin α × cos ß + cos α × sin ß

✒ α = (a + b) & ß = c

➡ sin (a + b) cos C + cos (A + B) sin C

➡ (sin A cos B + cos A sin B) cos C + (cos A cos B - sin A sin B) sin C

➡ sin A cos B cos C + sin B cos C cos A + sin C cos A cos B - sin A sin B sin C

➡ cos A cos B cos C (tan A + tan B + tan C - tan A tan B tan C)

Hence, it is solved...

Step-by-step explanation:

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