Question

derive the formula:v^2=u^2+2as.​

Answer 1

DERIVATION OF EQUATION OF MOTION :

▪️ V² = u² + 2as

Here,

Displacement, distance, time, acceleration, speed and velocity are described from the above formula.

We know the first equation of motion,

▪️ V = u + at

So, V = u + at --------(i)

$\implies \tt S \ = \ \bigg( U \ + \ \dfrac {v}{2} \bigg) \ \times \ 2$

$\implies \tt \dfrac {s}{t} \ = \ u \ + \ \dfrac {v}{2}$

$\implies \tt u \ + \ v \ = \ 2 \ \times \ \dfrac {s}{t}$

$\implies \tt u \ + \ v \ = \ \dfrac {2s}{t}$ --------(ii)

Now, From the above two equations.

Substituting equation (i) and (ii)

We get,

$\implies \tt (v \ - \ u) \ (v \ + \ u) \ = \ at \ \times \ \dfrac {2s}{t}$

$\implies \tt v^{2} \ - \ u^{2} \ = \ 2as$

$\therefore \red {\boxed {\tt v^{2} \ = \ u^{2} \ + \ 2as}}$

•°• Hence derived ✔︎

Answer 2

Answer:

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