Question

Derive the formulas of frustum of a cone for the following:
1. CSA
2. TSA
3. VOLUME..


PLEASE DERIVE ALL OF THE ABOVE STEP BY STEP...
Thanks#class10.

Answer 1

there is our answer

Answer 2

ʀᴇᴠɪsɪᴏɴ ᴏғ ғᴏʀᴍᴜʟᴀs ᴏғ ᴍᴇɴsᴜʀᴀᴛɪᴏɴ ᴄʜᴀᴘᴛᴇʀ

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♦ CSA of cuboid ➾ 2(bh + hl)

♦ TSA of Cuboid ➾ 2(lb + bh + hl)

♦ Volume of Cuboid ➾ Length × Breadth × Height

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♦ CSA of cube ➾ 4L²

♦ TSA of Cube ➾ 6L²

♦ Volume of Cube ➾ Length³

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♦ CSA of  Right Circular Cylinder ➾ 2πrh

♦ TSA of  Right Circular Cylinder ➾ 2πr(r + h)

♦ Volume of  Right Circular Cylinder ➾ πr²h

♦ CSA of Right Circular Hollow Cylinder ➾ 2πh(r + R)

♦TSA of Right Circular Hollow Cylinder  ➾ 2π(r + R) (h + R – r)

♦  Volume of Right Circular Hollow Cylinder  ➾ πh(R² – r²)

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♦ CSA of Right Circular Cone ➾ πrl

♦ TSA of Right Circular Cone  ➾ πr(r + l)

♦ Volume of Right Circular Cone  ➾ ⅓ (πr²h)

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♦ CSA of Sphere ➾ 4πr²

♦ TSA of Sphere   ➾ 4πr²

♦ Volume of Sphere   ➾ 4/3 (πr²)

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♦ CSA of Hemisphere ➾ 2πr²

♦ TSA of  Hemisphere ➾ 3πr²

♦ Volume of  Hemisphere ➾ 2/3 (πr²)

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♦ CSA of Frustum ➾ πl(r + R)

♦ TSA of  Frustum  ➾ πl(r + R) + p(r² + R²)

♦ Volume of  Frustum  ➾ ⅓πh(r² + R² + rR)