Question

Derive the joule thomson coefficient for an real gas

Answer 1

Answer:

It can be derived from volumetric properties: (2.34) The Joule–Thomson coefficient of an ideal gas is zero. In real gases, the Joule–Thomson coefficient is different from zero and depends on pressure and temperature. For ηJT > 0, temperature decreases, and for ηJT < 0, temperature increases during an expansion.