Derive the Kinametic equation v=u+at
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Answer:
Let the velocity of an object increase from u m/s to v m/s in time t
Let the velocity of an object increase from u m/s to v m/s in time tThen the rate of change of velocity with respect to time is given by
Let the velocity of an object increase from u m/s to v m/s in time tThen the rate of change of velocity with respect to time is given by(v - u)/t. This quantity is called acceleration and given the symbol a
Let the velocity of an object increase from u m/s to v m/s in time tThen the rate of change of velocity with respect to time is given by(v - u)/t. This quantity is called acceleration and given the symbol aThat is (v - u)/t = a
Let the velocity of an object increase from u m/s to v m/s in time tThen the rate of change of velocity with respect to time is given by(v - u)/t. This quantity is called acceleration and given the symbol aThat is (v - u)/t = av - u = at ………..multiplying both sides by t
Let the velocity of an object increase from u m/s to v m/s in time tThen the rate of change of velocity with respect to time is given by(v - u)/t. This quantity is called acceleration and given the symbol aThat is (v - u)/t = av - u = at ………..multiplying both sides by tv = u + at ………….adding u to both sides
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Answer:
a = (v-u)/t. From this, v-u = at and v=u + at which proves the result. Representing v as a derivative, that is, v = ds/dt where s is the distance moved in time 't', and integrating w.r.t. 't' from 0 to t, one finds s = ut + (1/2)at^2.