Derive the kinematic equation for displacement(x) = 0 and time(t)= 0.
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Answered by
0
Answer:
answer is 0
Explanation:
because displacement is 0
time is 0
Answered by
1
Answer:
Let a particle moves from point A with intial speed u , with constant acceleration particle reaches the point B where its speed became v ,time taken by particle from A to B is t .
See attachment,
slope of v- t time graph = Acceleration
(v - u)/t = a
v = u + at [ formula] -----(1)
Now, To find displacement, find area inclosed by v-t graph
so, displacement = area incosed by v- t graph
= 1/2 [ v + u] t
= 1/2 (u + at + u)t [ from equation (1)
= ut + 1/2 at²
Hence , S = ut + 1/2 at² [formula]-----(2)
Now, v = u + at
squaring both sides,
v² = u² + a²t² + 2uat
= u² + 2a[ut + 1/2at²]
= u² + 2aS [ from equation (2)
Hence, v² = u² + 2aS [ formula]
Please brainlest me the answer
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