Question

Derive the kinematic equations of motion for constant acceleration.

Answer 1

Answer:

Hope it helps you......

Answer 2

Answer:

Let a particle moves from point A with intial speed u , with constant acceleration particle reaches the point B where its speed became v ,time taken by particle from A to B is t .

See attachment,

slope of v- t time graph = Acceleration

(v - u)/t = a

v = u + at [ formula] -----(1)

Now, To find displacement, find area inclosed by v-t graph

so, displacement = area incosed by v- t graph

= 1/2 [ v + u] t

= 1/2 (u + at + u)t [ from equation (1)

= ut + 1/2 at²

Hence , S = ut + 1/2 at² [formula]-----(2)

Now, v = u + at

squaring both sides,

v² = u² + a²t² + 2uat

= u² + 2a[ut + 1/2at²]

= u² + 2aS [ from equation (2)

Hence, v² = u² + 2aS [ formula]