Question

derive the law of conservation of momentum​

Answer 1

Explanation:

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Answer 2

and = let a bo

let a A body of mass M1 moving with the velocity u1 and another body B of mass M2 moving with velocity u2

then their momentum are m1u1 and m2u2 respectively.

let u1 greater than u2 then the two bodies collide with each other

let after collision their velocities become v1 and v2 respectively

then their momentum after collision become m1v1 and m2v2 respectively

so rate of change of momentum of the body A

= m1v1-m1u1/t

and that of body B is m2v2-m2u2/t

according to Newton second law rate of change of momentum is directly proportional to the force

so, F1 = m1v1-m1u1/t

and F2 = m2v2-m2u2/t

now according to the third law of motion F1 = F2

thus m1v1-m1u1/t = m2v2-m2u2/t

cancelled t from both sides we get

m1v1-m1u1= m2v2-m2u2

= m1v1+m2v2= m1u1+m2u2

proved

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