Question

derive the law of conservation of momentum

Answer 1

☆☆ AS-SALAMU-ALYKUM ☆☆

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LAW OF CONSERVATION OF MOMENTUM :-
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STATEMENT :-
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LAW OF CONSERVATION OF MOMENTUM STATES THAT MOMENTUM OF A BODY REMAINS CONSERVE BEFORE AND AFTER COLLISION .

IF THERE IS NO EXTERNAL ISOLATED FORCE APPLIED ON A BODY THEN MOMENTUM OF BODY REMAINS CONSERVED

MATHMATICALLY :-
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Pf=Pi

Or

mvf = mvi

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delta F=delta P÷t

AS THERE IS NO EXTERNAL FORCE APPLIED THAT IS FORCE IS ZERO

SO

0=delta P ÷ t

delta P = 0 × t

delta P = 0

final momentum _ delta P means initial momentum

Pf _ Pi = 0

Pf = Pi

THAT IS FINAL MOMENTUM = INITIAL MOMENTUM

SO THIS IS LAW OF CONSERVATION OF MOMENTUM

(F=DELTA P ÷ T ,,,,IS THE REAL EQUATION OF NEWTON SECOND LAW )

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Answer 2

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┗─━─━─━─━∞◆∞━─━─━─━─┛

Conservation 0f Momentum➫ A system in which the momentum of a system is constant if there are no external forces acting on the system.

Prove: Conservation 0f Momentum:-▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃⤵

➧Let the Body A = m1 & B = m2

➧Let their velocity be u1 & u2
(u1 > u2)

➧Momentum of Body
A = m1u1 & B = m2u2

❱ Initial & Final momentum of System
➾ m1u1 + m2u2

◉ Body A exert force of Action
➾ Fᴀʙ on Body B.

◉ Body B exert force of Reaction
➾ Fʙᴀ on Body A.

▸ Fᴀʙ = Body A
➾ m1 (v1 - u1) / t

▸ Fʙᴀ = Body B
➾ m2 (v2 - u2) / t

▸ Since, Action = - reaction
▸ So, Fᴀʙ = - Fʙᴀ

m1 (v1 - u1) / t = - m2 (v2 - u2) / t

▸ m1v1 - m1u1 = m2v2 + m2u2
▸ m1v1 - m2v2 = m1u1 + m2u2...✔

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Thanks...✊