Physics, asked by vdcharan564, 5 months ago

Derive the lens formula


Answers

Answered by Anonymous
2

  1. The figure above shows that formation of a real, inverted and diminished image A'B' of the object AB placed beyond the centre of curvature at a distance u from the convex lens. ...
  2. According to Cartesian sign convention,
  3. Object distance (OB) = -u.
  4. Image distance (OB') = +v.
  5. Focal length (OF1 = OF2) = +f.
Answered by kambojnamar
0

Answer:

this is the answer

Explanation:

  • he figure above shows that formation of a real, inverted and diminished image A'B' of the object AB placed beyond the centre of curvature at a distance u from the convex lens. ...
  • he figure above shows that formation of a real, inverted and diminished image A'B' of the object AB placed beyond the centre of curvature at a distance u from the convex lens. ...According to Cartesian sign convention,
  • he figure above shows that formation of a real, inverted and diminished image A'B' of the object AB placed beyond the centre of curvature at a distance u from the convex lens. ...According to Cartesian sign convention,Object distance (OB) = -u.
  • he figure above shows that formation of a real, inverted and diminished image A'B' of the object AB placed beyond the centre of curvature at a distance u from the convex lens. ...According to Cartesian sign convention,Object distance (OB) = -u.Image distance (OB') = +v.

he figure above shows that formation of a real, inverted and diminished image A'B' of the object AB placed beyond the centre of curvature at a distance u from the convex lens. ...According to Cartesian sign convention,Object distance (OB) = -u.Image distance (OB') = +v.Focal length (OF1 = OF2) = +f.

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