Derive the mathematical formulation for Newton's second law of motion
CBSE Class IX Science SA 2 (3 Marks)
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Change in momentum cc P1 - P2 cc my — my cC m (v — u)
Rate of change of momentum cc m(v - u)
m(v - u) F oc t
Since, (a = v -tuj
t
(By second law of Newton, rate of change of momentum = Force)
.-. Fccma or F = kma = k = 1 (k = 1 by experiments) F = ma
Rate of change of momentum cc m(v - u)
m(v - u) F oc t
Since, (a = v -tuj
t
(By second law of Newton, rate of change of momentum = Force)
.-. Fccma or F = kma = k = 1 (k = 1 by experiments) F = ma
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