Question

Derive the position-time equation using distance-time graph​

Answer 1

Answer:

Consider the graph shown in the given attachment. Obviously, the total distance s travelled by the object in time t is given by are under v-t graph. Obviously, OABGC is a trapezium, whose area is (OA + BC/2) × OC. Therefore, this equation is the position velocity relation for uniformly accelerated motion.