Derive the relation 1/R= 1/R1+1/R2+1/R3 when three resistors R1,R2,R3 are connected in parallel in an electrical circuit?
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Answered by
77
here's your answer
ammeter reading when connected to ina series to the circuit I=I1+I2+I3
voltmeter reading must be constant V=IR
I1=V/R1
I2=V/R2
I3=V/R3
on adding the three equation
I1+I2+I3=V/R1+V/R2+V/R3
I= v[1/R1+1/R2+1/R3]
I/V=". "
SO R=1/R1+1/R2+1/R3. V/I=R
ammeter reading when connected to ina series to the circuit I=I1+I2+I3
voltmeter reading must be constant V=IR
I1=V/R1
I2=V/R2
I3=V/R3
on adding the three equation
I1+I2+I3=V/R1+V/R2+V/R3
I= v[1/R1+1/R2+1/R3]
I/V=". "
SO R=1/R1+1/R2+1/R3. V/I=R
Answered by
2
Answer:
written below-
Explanation:
consider three resistance R1 , R2, R3 , these three resistance are connected in parallel.
total current across resistors is given by ,
I = I1 + I2 + I3
according to the ohm's law ,
V= IR
in parallel combination voltage remains constant
so, V/R= V/R1 + V/R2+ V/R3
1/R= 1/R1+ 1/R2+ 1/R3
#SPJ2
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