Physics, asked by davidtakhellambam, 8 months ago

Derive the relation between Current and drift velocity? Show the current density is directly proportional to drift velocity.

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Answered by Divyansh50800850
1

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∴ Total number of electrons in the Conductor = Volume x electron density = Al x n . Under the influence of this field E, free electrons begin to drift in a direction opposite to that of the direction of field. where, vd is the drift velocity of electrons. Thus, current density is proportional to drift velocity.

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Answered by mansimisra1
0

Answer:

Relation between drift velocity (Vd) and current density(J).

NOW SEE THE 1ST ATTACHMENT

Considered a current carrying conductor of length (l) and area of cross section (A). The free electron density of this conductor be “n” electrons/metre³.

when a potential difference V voltage applied across its end then the electric field E is produced and free electron are move in the direction opposite to the electric field by the drift velocity.

“Drift velocity”: Drift velocity is define as the average velocity with which the electrons get drifted towords positive end of the conductor under the influence of an external electric field. it is denoted by Vd.

Thus, Vd = l/t = (U+V)/2

The Free electron density of a conductor be “n” electrons/metre ³.

i.e 1m³ volume containing = n free electron

Hence,

(AL) m³ Volume containing (N) = n.(AL) electrons

Thus, amount of charge flows through any cross section of a conductor,Q = N.e We know that

Current, I = Q/t

Hence, I = ( .e)/t

I = n.e.A(l/t)

{By the definition

Drift velocity,Vd = l/t }

I = n.eA(Vd)

And current density, J = I/A

J = (n.e.A.Vd)/A

J = n.e.Vd

Here the quantity (n.e) is constant term

Hence, [ J ∝ Vd ]

Thus the current density of a current carrying conductor is directly proportional to the Drift velocity of free electron.

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