Question

derive the relation between Kp, kc&kx​

Answer 1

Answer:

Explanation:

Consider an example

2A(g)+B(g) ⇋ 2C(g) All in the gas phase.

The Kp is given by-

Kp=P2CP2APB ———(1)

Ideal Gas Equation

Each of these ideal gas molecules behaves similarly. So for each of them,

PV = nRT

On rearranging we get-

P=nVRT

Substituting these in equation (1)

⇒Kp=[C]2(RT)2[A]2(RT)2[B](RT) ⇒Kp=[C]2[A]2[B]×(RT)2(RT)2(RT)

On canceling like terms and substituting Kc=[C]2[A]2[B] we get-

⇒Kp=KcRT

Or

Kp=Kc(RT)−1

In general,

Kp=Kc(RT)Δn

Where, Δn represents the change in the number of moles of gas molecules. [That is Δn = product – reactant in moles only for gas molecules]

When the change in the number of moles of gas molecules is zero, that is Δn = 0

⇒ Kp=Kc

In general, for any chemical reactions of gas molecules relation between Kp And Kc is-

Kp=Kc(RT)Δn

Kc=Kp(RT)−Δn

Answer 2

Answer:

Hey ur answer

Explanation:

Kc=kp(Rt) - &£n