Derive the relation between momentum and kinetic energy ??????
Answers
Answered by
19
As we know K.E.=1/2×m×v^2..(1)
p=m×v..(2)
substituting the value of v in (1) we get
p^2=2×m×K.E
p=m×v..(2)
substituting the value of v in (1) we get
p^2=2×m×K.E
Answered by
33
KE of a body given by : (1/2)×m×(v^2)....(1)
where m is mass and v is velocity of the body .
multiplying and dividing equation (1) by m we get:
KE = (1/2)×m×v×v×(m/m)
=(1/2)×(mv)×(mv)/m.........(2)
we know that linear momentum (P) of a body is given by :
P=mv..............(3)
place value of P from (3) into (2) we get ,
KE =[1/(2m)]×P^2
where m is mass and v is velocity of the body .
multiplying and dividing equation (1) by m we get:
KE = (1/2)×m×v×v×(m/m)
=(1/2)×(mv)×(mv)/m.........(2)
we know that linear momentum (P) of a body is given by :
P=mv..............(3)
place value of P from (3) into (2) we get ,
KE =[1/(2m)]×P^2
Similar questions