Derive the relation between refractive index of a medium and its critical angle
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Answer:
n= 1 / sin C
Explanation:
n1 sin I = n2 sin r
n1/ n2 = sin r / sin I
n1/ n2 = sin 90 / sin c= 1/ sin c
n = 1/ sin c
because I= c when r= 90 °
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