derive the relation e =v+lr
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Consider two points A and B separated by a small distance dx in an electric field.
Since dx is small, the electric field E is assumed to be uniform along AB. The force acting on a unit positive charge at A is equal to E.
Now, the work done in moving a unit positive charge from A to B against the electric field is dW=−E×dx.
The negative sign shows that the work is done against the direction of the field. Since the work done is equal to potential difference dV between A and B then dV=−E×dx or E=−
dx
dV
Thus, the electric field at a point is the negative of the potential gradient at that point.
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