Physics, asked by rashidkalodi4772, 8 months ago

Derive the relation for minimum and maximum acceleration velocity and displacement in shm

Answers

Answered by s02371joshuaprince47

Answer:

d²Y/dt² is acceleration of SHM , d²Y/dt² = w²Asin(wt ± ∅ + π) hence , phase difference between acceleration and velocity is π/2 and acceleration and displacement is π

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