Physics, asked by khushinayak2308, 3 months ago

Derive the relation P= 1/3 mnv2

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Answered by khinarampatle
6

Answer:

Derivation of pV = 1/3Nmc2

The Kinetic Theory of Gases and the Ideal Gas Equation

ASSUME:

Ideal gases are composed of:

- Numerous

- elastic molecules

- of Negligible Size compared to Bulk Container

- whose Thermal Motion is 'Random'

Consider a rectangular box length l, area of ends A, with a single molecule travelling left and then right the length of the box because of a collision with the end wall.

The time between collisions with the left wall is the distance of travel between wall A and the other wall divided by the speed of the particle in the x-direction, u.

t = 2 L - (equation 1)

u

According to Newton, force is the rate of change of the momentum

F = D (m u)

Dt

The momentum change upon collision is the momentum after the collision minus the momentum before the collision To hit the left wall the initial velocity must have been -u, so:

change in momentum, D (m u) = m u - (-m u) = 2m u

The average force on the left end wall is the rate of change of momentum

F = 2m u

Dt

Combine equation (1) into the above equation and we get:

F = 2m u

(2 L /u)

The 2's cancel and the formula reduces to:

F = m u2

L

The pressure, p, exerted by this single molecule constrained to move in one horizontal direction (one dimension) is the average force per unit area

p = F = m u2 = m u2

A L . A V

where V = A . L is the volume of the rectangular box.

Now consider N gas molecules in the box

p = Nm u2

V

But they could be moving moving with velocities in ALL directions - not just horizontally. They could be moving in the:

x direction (ux)

y direction (uy)

z direction (uz)

Using the rule for adding vectors at right angles to each other - we have to use Pythagoras to add the three velocities. (Square all the velocities and add them)

"mean square speed" of the gas molecules: c2 = ux2 + uy2 + uz2

but on average only a third of all molecules will be moving in any given direction,

so ux2 = uy2 = uz2

and so c2 = 3 ux2 OR ux2 = 1/3 c2

If the molecules are free to move in three dimensions, they will hit walls in one of the three dimensions one third as often. The pressure then of a gas sample of N molecules in 3-D is

p = 1 Nmc2

3 V

pV = 1 Nmc2

3

where p = gas pressure

V = gas volume

N = number of molecules

m = mass of each molecule

c2 = mean square speed of the gas molecules

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