Question

Derive the relation -- pH + pOH=14

Answer 1

it is the sum of Ionic Equilibrium so that the pH and pohis equal to 14

Answer 2

[H+] +[OH] =10^-14=Kw

take log on both side

Iog10{[H+]+[OH] }=log10^14=logKw

log10[H+] +log10[OH-]=(-14)log10=log10Kw

Multiply throughout "minus(-) sign

{log10[H+]} +{log10[OH-]}=-(-14)log10=log10

PH+POH=14=PKW

PH+POH=14

I hope it helps......