Question

Derive the relation snth = ( 2n-1) where snth = distance travelled in n th second

Answer 1

ANSWER

snth=μ+2a(2n−1)

The real formula is ; 

μ(1)+2a(1) (2n - 1 ) 

where 1 represent    1 sec   as times

LHS = [ L ]

[ L ]  = μ(1)=[LT−1][T]

                             = [ L ]

aa(1)[2n−1] = LT−2 [ T ] [ T ]

                                         = L 

[ L ] = [ L ] + [ L ]