Question

Derive the relationship between co-efficient of linear expansion, coefficient

of area expansion and coefficient of volume expansion​

Answer 1

Answer:

it's simple bro

Explanation:

use error method

Answer 2

☆ ΛПƧЩΣЯ ☆

➢Co-efficient of linear expansion :

Consider a rod of length L when it is heated the lenght charges by ΔL,so the new length is L+ΔL.

This fractional change is directly proportional to change in temperature.

$\frac{Δl}{l} \: \alpha \: Δt \: \\ or \\ \frac{Δl}{l} = Δt$

$where \: \: \alpha \: \: \: is \: co \: efficient \: of \: \\ linear \: expansion$

$\alpha = \frac{ \frac{Δl}{l} }{Δt}$

➢Co efficient of Area expansion :

When a solid is heated fractional change in area and directly proportional to change in temperature.

$\frac{Δa}{a} \: \alpha \: Δ t \\ or \\ \frac{Δa}{a} \: \beta Δt$

$where \: \beta \: is \: co \: efficient \: of \: area \\ expansion. \\ \beta = \frac{ \frac{Δa}{a} }{Δt}$

➢Co efficient of volume expansion :

When a solid is heated the fractional change in volume is directly proportional to change in temperature.

$\frac{Δv}{v} \: \alpha Δt \\ or \\ \frac{Δv}{v} \: \gamma Δt$

$where \: \gamma \: is \: co \: efficient \: of \: \\ volume \: expansion. \\ \gamma = \frac{ \frac{Δv}{v} }{Δt}$

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