Physics, asked by devarajrv761, 4 months ago

derive the relationship between electric field intensity and potential difference

Answers

Answered by sᴡᴇᴇᴛsᴍɪʟᴇ

Electric field intensity is equal to the negative of rate of change of potential with respet to the distance or it can be defined as the negative of the rate of derivative of potential difference, V with respect to r, E = - dV/dr

Answered by LEGEND778

Answer:

The relation is very simple. Electric field intensity is equal to the negative of rate of change of potential with respet to the distance or it can be defined as the negative of the rate of derivative of potential difference, V with respect to r, E = - dV/dr.

Explanation:

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