Question

Derive the relationship between relative lowering of vapour pressure and molar mass of the solute.​

Answer 1

Answer:

Relationship b/w relative lowering power of Vapour pressure and molality.

Relative lowering of vapour pressure is one of the colligative properties.Collegative property are those property of solution which depends only on the number of solute particles and independent of the nature of the solute particles.

Relative lowering of vapour pressure is the ratio of lowering of vapour pressure to the vapour of pure solvent. It is given as---

p0 - p/p0 = xB

Where,

p0 = Vapour pressure of pure solvent.

p= Vapour pressure of solution containing non-volatile Solute.

xB = Mole fraction of solute.

Now, this Relative lowering of Vapour pressure is related to the molality of solution by the following mathematical expression-----

p0 - p/p0 = m× MA/1000

p0 - p/p0 = m× MA/1000Where,

m= molality of solution and

p0 - p/p0 = m× MA/1000Where, m= molality of solution andMA= molar mass of the solvent.

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