Derive the relationship between the heat of reaction at constant pressure and at constant volume
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Dear Student,
H = U + PVor, ∆H=∆U+∆(PV)For an ideal gas, ∆(PV)=nR∆TSo,∆H=∆U+nR∆TDividing with ∆T∆H∆T=∆U∆T+ nRand, ∆H∆T= Cp∆U∆T=CvTherefore, Cp= Cv+nRor, Cp−Cv=nR
H = U + PVor, ∆H=∆U+∆(PV)For an ideal gas, ∆(PV)=nR∆TSo,∆H=∆U+nR∆TDividing with ∆T∆H∆T=∆U∆T+ nRand, ∆H∆T= Cp∆U∆T=CvTherefore, Cp= Cv+nRor, Cp−Cv=nR
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0 order ! Rate = k [A]^0. , where everything has its usual meanings. So , mathematically, Rate= k. The units will be the same.
P.S : This question was in the ISC 2016 Chemistry board paper.
P.S : This question was in the ISC 2016 Chemistry board paper.
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