Question

derive the relationship between wavelength and momentum of an electron in an atom
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Answer 1

Answer:

E = mc ^2..........(1)

E = hf ............ (2)

equating

mc^2 = hf ( f = c / lambda )

mc^2 = h c/lambda

c and c cancelled

mc = h /lambda

or lambda , wavelength of electron = h/mc (c nearly=v) or lambda = h/mv (mv = p, momentum) or lambda = h /p