Question

derive the second and third equation of motion ?

Answer 1

2nd equation

Points

i.Vavg (average velocity)=u+v/2

ii.S=Vavg*t

iii.v=u+at

Derivation:-

S= Vavg*t

S=(u+v/2)*t [vavg=u+v/2]

S=ut/2 + (u+at/2)*t

S=ut/2 + ut/2 +1/2at^2

So, S=ut+1/2at^2

3rd equation

S=u(v-u)/a + 1/2a + (v-u/a) * (v-u/a)

S=[2uv-2u^2+(v-u)^2]/ 2a

2as= 2uv- 2u2 + v^2 + u^2 - 2uv

= -u^2 + v^2

v^2 = u^2+2as