Derive the second equation of motion by graphical method.
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distance is the area of the trapezium OABD
s=area of trapezium
=1/2×height×(sum of parallel lsides)
=1/2×AC×(OA+BD)
=1/2×t×(u+v)
=1/2×t(u+u+at)[from equation v=u+at]
=1/2×2ut/2+at^2/2
=s=ut+1/2at^2
s=area of trapezium
=1/2×height×(sum of parallel lsides)
=1/2×AC×(OA+BD)
=1/2×t×(u+v)
=1/2×t(u+u+at)[from equation v=u+at]
=1/2×2ut/2+at^2/2
=s=ut+1/2at^2
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