Question

derive the second law of motion in graphical

Answer 1

momentum is directly proportional to force .p=mg

Answer 2

$➡ { \color{red}{To \: Derive \: 2nd \: equation \: of \: motion \: [Graphically]}}$

${ \bold{ \underline{★ s = ut + ½ at²}}}$

➡ Consider the velocity time graph of a body shown in attachment. The body has an initial Velocity u at point A and then velocity changes from A to B at a uniform rate in time t. There's uniform acceleration a from A to B,and after time t the final Velocity is v which is equal to BC. The time t is represented by OC. Through construction we drew perpendicular CB from point C,and AD parallel to OC. BE is perpendicular to the point B to OE.

Here,

• Initial Velocity (u) = OA

• Final Velocity (v) = BC

• Time (t) = OC

➨Distance Covered = Area of the figure OABC

➨ Area of OABC = Area of OADC + Area of ABD

➨ Distance (s) = Area of OADC + Area of ABD

➨s = (OA × OC) + (½ × AD × BD)

➨s = (u × t) + (½ × t × at)

➨s = ut + ½ at²

\therefore∴ The 2nd equation of motion is derived here graphically.