Question

derive the statement " when no external force act on body its momentum will constant"​

Answer 1

Answer:

The law of conservation of momentum can be explained from the second law of motion. Newton’s second law of motion says that rate of change of linear momentum of a body is equal to the net external force applied on it.

Mathematically it is expressed as:

dP/dt

=(mv/)dt

=m dv/dt

=ma

=Fnet

If the net external force acting on a body is zero, then the rate of change of momentum is also zero, which means that there is no change in momentum.

HOPE THAT IT WAS HELPFUL!!!!

Explanation:

Answer 2

Explanation:

The law of conservation of linear momentum states that if no external forces act on the system of two colliding objects, then the vector sum of the linear momentum of each body remains constant and is not affected by their mutual interaction.

Alternatively, it states that if net external force acting on a system is zero, the total momentum of the system remains constant.

Proof:

Let us consider a particle of mass ‘m’ and acceleration ‘a’. Then, from 2nd law of motion,

Law of Conservation of Linear Momentum

If no external force acts on the body then, F=0,

Law of Conservation of Linear Momentum

Therefore, ‘P’ is constant or conserved.

(Note: If the derivative of any quantity is zero, it must be a constant quantity.)

Deduction of Law of Conservation of linear momentum for two colliding .(open the link to show photo)

(https://notes.tyrocity.com/wp-content/uploads/momentum-conservation.png)

Deduction of Law of Conservation of linear momentum for two colliding bodies

Let us consider two bodies of masses m1 and m2 moving in straight line in the same direction with initial velocities u1 and u2. They collide for a short time ∆t. After collision, they move with velocities v1 and v2.

From 2nd law of motion,

Force applied by A on B = Rate of change of momentum of B

FAB = (m2v2-m2u2)/∆t

Similarly,

Force applied by B on A = Rate of change of momentum of A

FBA = (m1v1-m1u1)/∆t

From Newton’s 3rd law of motion,

FAB = -FBA

Or, (m2v2-m2u2)/∆t = -(m1v1-m1u1)/∆t

Or, m2v2-m2u2 = -m1v1+m1u1

Or, m1u1 + m2u2 = m1v1 + m2v2

This means the total momentum before collision is equal to total momentum after collision. This proves the principle of co conservation of linear momentum.