Question

derive the trajectory formula of the projectile -y =ky^2​

Answer 1

Answer:

Let A be the initial point of projection and B be the point of maximum height

K.E

B

=

2

1

mv

2

cos

2

θ

K.E

A

=

2

1

mv

2

Now, K.E

A

=

4

3

K.E

B

⇒cosθ=

2

3

⇒θ=30

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