Derive the valency of the element with number of neutrons = 22 and ,
atomic mass = 40 u
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Atomic mass is 40 u
No.of neutrons =22
Atomic number = Atomic mass – no.of neutrons
Atomic number=40-22=18
Element is Argon(Ar).
Argon is an inert gas.It's valency is 0
No.of neutrons =22
Atomic number = Atomic mass – no.of neutrons
Atomic number=40-22=18
Element is Argon(Ar).
Argon is an inert gas.It's valency is 0
Answered by
1
Hi friend ,
Atomic mass = No. of protons + No. of neutrons
40u = No. of protons + 22
40-22 = No. of protons
18 = No. of protons
No. of protons = Atomic no.
Atomic no. = 18
Electronic configuration = 2,8,8
The valency of the element is 0. Because it has valence electrons as 8(octet).
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Hope this helped u..
PLZ MARK AS BRAINLIEST..
Atomic mass = No. of protons + No. of neutrons
40u = No. of protons + 22
40-22 = No. of protons
18 = No. of protons
No. of protons = Atomic no.
Atomic no. = 18
Electronic configuration = 2,8,8
The valency of the element is 0. Because it has valence electrons as 8(octet).
=============================
Hope this helped u..
PLZ MARK AS BRAINLIEST..
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