Question

Derive third equation of motion from velocity -time graph.​

Answer 1

Answer:

Hope you'll Understand it

Answer 2

Answer:

In case of uniform accelerated motion in any direction:

Acceleration,

 a=ΔtΔV=ACBC=tV−V0V=V0+at ..... (First equation of motion)

Now ,area of v-t graph =total displacement

s=OA×OD+21×AC×BC

=Vot+21t(V−V0)

s=V0t+21t×at ...(Second equation of motion)

Now s= area of trapezium OABD

=21×(OA+BD)×AC=