Question

Derive third equation of motion i.e V2-U2=2as by using velocity- time graph.
5 points​

Answer 1

Explanation:

consider second equation

s=ut+1/2 at^2

multiply by 2 on both sides

2s=2ut+ 2×1/2at^2

but u know that

t=v-u/a

substitute value of t in above equation

2s=2u(v-u)÷a+a{(v-u)/a}^2

2s=2uv-2u^2/a +v^2-u^2/a

2as=2uv-2u^2+v^2+u^2 -2uv

2as=v^2+u^2-2u^2

2as=v^2-u^2