Question

Derive third equation of motion v^2 _u^2 = 2as numerically.
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Answer 1

Answer:

hello the derivation of v^2=u^2+2as

Explanation:

v=u+at

s=ut+1/2 at^2

Now the derivation:

From the first equation we have :

at=v−u  

t=v−u\a  

Now putting the value of t in the second equation of motion:

s=u(v−u\a)+1\2a(v−u\a)2  

s=uv−u2\a+a(v2+u2–2vu)\2a2  

s=uv−u2\a+(v2+u2+2vu)\2a  

s=(2uv−2u2+v2+u2–2vu)\2a  

2as=v2−u2  

v2=u2+2as  

So here it is.. hope it helps