derive third equation of motion V square minus u square is equal to 2 years graphically
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Derivation of : v²-u²=2as
Consider velocity-time graph of an object that moves with uniform acceleration.
Distance= Area of trapezium OABC
Here is the graph :: https://bit.ly/2CeH4rn
S = 1/2(Sum of parallel sides) × (Distance between parallel sides)
=1/2 (OA+BC) × OC
Here,OA= u
OC= t
CB= v
S= 1/2(u+v)t --------> (1)
But a = v-u/t
t= v-u/a --------> (2)
Substituting (2) in (1) we get,
S= 1/2 (u+v) (v-u/a)
= 1/2 (v+u) (v-u/a)
u/1 = 1(v²-u²)/2-a
∴v²-u²= 2as
Hence derived!
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