Question

derive time flight of a projectile​

Answer 1

Answer:

The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 ⁡ θ i 2 g . The time of flight of an object, given the initial launch angle and initial velocity is found with: T=2visinθg T = 2 v i sin ⁡ .

Answer 2

Answer:

To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time. At maximum height, vy = 0. The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity.