Question

Derive using heron's formula that the area of an equilateral triangle is √3a^2 /4
Please solve ASAP​

Answer 1

Step-by-step explanation:

S=a+b+c/2

In equilateral traingle side a, a, a

S=3a/2

Then the area of traingle =sqrt s(s-a) +s(s-b) +s(s-c)

Sqrt3a/2(3a/2-a)+3a/2(3a/2-a)+3a/2(3a/2-a)

So slve this the result is sqrt3a^2/4