Question

Derive,
v^2=u^2+2as
genuine ans only .you are gonna be reported if wrong and if it is correct i will mark you as brainliest.

Answer 1

Answer:

from second equation of motion we have

s= ut + 1/2at^2.................(1)

and from first equation of motion we have

v = u+ at ..............(2)

this can be rearranged and written as:

at = v- u

t=. v-u/a

putting this value of t in first equation (1) we get ;

s= u(v-u)/a + 1/2a(v-u/a)^2

s= UV - u^2/a. + a( v^2 + u^2-2uv)/2a^2

s= uv- u^2/a + v^2+2uv/2a

2as= v^2- u^2

v^2= u^2 + 2as

Thanks for my answer