Question

derive v^2=u^2+2as please help​

Answer 1

✍SOLUTION: -

✪CONCEPT:-

=> To derive this, we need to know the other equations of motion:-

● V=u+at

●S=ut+1\2at^2

✪DERIVATION: -

From the first equation,

》 at = v−u

》 t = v−u/a

Put the value of t in the second equation of motion:

$s = u(v - u ) \div a \: + 1 \div 2 \times a \times( (v - u) \div a) {}^{2}$

$s=uv−u^2 \div a+a(v^2+u^2–2vu) \div 2a^2$

$s=uv−u^2 \div a+(v^2+u^2+2vu) \div 2a$

$s=(2uv−2u^2+v^2+u^2–2vu) \div 2a$

$= > 2as=v^2−u^2$

Hence,

$\boxed{v {}^{2} =u {}^{2} +2as}$

HENCE PROVED

HOPE IT HELPS :)