derive v=u+at And s=ut+ 1/2 at2
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To derive : The equations ....
v = u + at
s = u + 1/2 at²
solution : let a particle moves with initial velocity u after time t, its velocity becomes v due to acceleration acting on particle is a.
see figure,
slope of velocity - time graph = acceleration
⇒(v - u)/(t - 0) = a
⇒v - u = at
⇒v = u + at .........(1)
area enclosed the velocity - time graph = displacement covered by particle
⇒area of trapezium formed as shown in figure = S
⇒S = 1/2 [v + u ] × t
from equation (1),
⇒S = 1/2 [u + at + u ] × t
⇒S = 1/2 [2u + at] × t
⇒S = ut + 1/2 at² ...........(2)
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