derive v2 = u 2 + 2as.
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For getting the third law of motion equation, we use both of the equations of motion
S = ut + 1/2at2 and v = u + at, include the time variant t
t = v – u/a
and use this to replace t wherever it appears in the second equation. So
S=ut + 1/2at2 becomes
S = u(v – u/a) + 1/2a (v – u/a)2
= 2aS = 2u(v−u)+(v−u)2
= 2aS = 2uv − 2u2 − v2 − 2uv −u2
= 2aS = v2 − u2
= v2 = u2 + 2aS
Explanation:
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