Question

) Derive: v2-u? = 2as​

Answer 1

Explanation:

Velocity Equations for these calculations:

Final velocity (v) squared equals initial velocity (u) squared plus two times acceleration (a) times displacement (s). Solving for v, final velocity (v) equals the square root of initial velocity (u) squared plus two times acceleration (a) times displacement (s)......

Answer 2

Answer:

We will use both of the equations of motion to reach the third equation of motion. This will require a bit of algebra.

S=ut+21at2andv=u+at, include the time variant t

There will be some situations when we do not have any information about time and so it would be a good idea to derive an equation that does not have a t term.

To do this, we rearrange our first equation to get 

t=av−u

and use this to replace t wherever it appears in the second equation. So

S=ut+21at2 becomes,

S=u(av−u)+21a(av−u)2

⇒2aS=2u(v−u)+(v−u)2

⇒2aS=2uv−2u2−v2−2uv−u2

⇒2aS=v2−u2

⇒v2=u2+2aS