derive values of trigonometric ratios for 30° and 60°
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Take a point P on →OY and draw PA perpendicular to →OX Then, ∠OPA = 60°. Now, produce PA to B such that PA = MB and join OB. Therefore, ∠POB = 30° + 30° = 60°; which shows that each angel of triangle OPQ is 60° . Hence ∆OPQ is equilateral.
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